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Return default_arguments from operator& of two default_arguments

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operator& should return combined values of the same type, not a new type
(i.e. bool).  This is much more verbose, but easier to reason about
without implied conversion.

Signed-off-by: Sean Robinson <sean.robinson@scottsdalecc.edu>
This commit is contained in:
Sean Robinson 2022-02-07 14:27:06 -07:00
parent 6a8b1318ec
commit 7cbc66f65b
1 changed files with 7 additions and 4 deletions
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11
include/argparse/argparse.hpp
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@ -332,8 +332,11 @@ enum class default_arguments : unsigned int {
all = help | version,
};
inline bool operator& (const default_arguments &a, const default_arguments &b) {
return static_cast<unsigned int>(a) & static_cast<unsigned int>(b);
inline default_arguments operator& (const default_arguments &a,
const default_arguments &b) {
return static_cast<default_arguments>(
static_cast<std::underlying_type<default_arguments>::type>(a) &
static_cast<std::underlying_type<default_arguments>::type>(b));
}
class ArgumentParser;
@ -857,7 +860,7 @@ public:
std::string aVersion = "1.0",
default_arguments aArgs = default_arguments::all)
: mProgramName(std::move(aProgramName)), mVersion(std::move(aVersion)) {
if (aArgs & default_arguments::help) {
if ((aArgs & default_arguments::help) == default_arguments::help) {
add_argument("-h", "--help")
.action([&](const auto &) {
std::cout << help().str();
@ -868,7 +871,7 @@ public:
.implicit_value(true)
.nargs(0);
}
if (aArgs & default_arguments::version) {
if ((aArgs & default_arguments::version) == default_arguments::version) {
add_argument("-v", "--version")
.action([&](const auto &) {
std::cout << mVersion;